2x^2+8x+22=x^2

Solution for 2x^2+8x+22=x^2 equation:

Simplifying
2x2 + 8x + 22 = x2

Reorder the terms:
22 + 8x + 2x2 = x2

Solving
22 + 8x + 2x2 = x2

Solving for variable 'x'.

Combine like terms: 2x2 + -1x2 = 1x2
22 + 8x + 1x2 = x2 + -1x2

Combine like terms: x2 + -1x2 = 0
22 + 8x + 1x2 = 0

Begin completing the square.

Move the constant term to the right:

Add '-22' to each side of the equation.
22 + 8x + -22 + x2 = 0 + -22

Reorder the terms:
22 + -22 + 8x + x2 = 0 + -22

Combine like terms: 22 + -22 = 0
0 + 8x + x2 = 0 + -22
8x + x2 = 0 + -22

Combine like terms: 0 + -22 = -22
8x + x2 = -22

The x term is 8x.  Take half its coefficient (4).
Square it (16) and add it to both sides.

Add '16' to each side of the equation.
8x + 16 + x2 = -22 + 16

Reorder the terms:
16 + 8x + x2 = -22 + 16

Combine like terms: -22 + 16 = -6
16 + 8x + x2 = -6

Factor a perfect square on the left side:
(x + 4)(x + 4) = -6

Can't calculate square root of the right side.

The solution to this equation could not be determined.